8-sinf algebra fanidan mavzulashtirilgan test.

8-sinf o'quvchilari uchun algebra fanidan
Sonning moduli. Modul qatnashgan tenglama va tengsizliklar mavzusi bo'yicha tuzilgan test savollari
Test savollar soni: 20 ta
Bajarish uchun ajratilgan vaqt: 40 daqiqa
Sizga omad yor bo'lsin!

Barcha ma'lumotlarni to'g'ri kiriting.

Tenglamani yeching: \(\left| x \right| - x = 2\)

-1

1

-2

2

Tengsizlikni yeching: \(\left| {x - \frac{1}{2}} \right| < \frac{3}{4}\)

\(x \ge 1\frac{1}{4}\;,\;x < - \frac{1}{4}\)

\(x > 1\frac{1}{4}\;,\;x < - \frac{1}{4}\)

\(x > 1\frac{1}{4}\;,\;x \le - \frac{1}{4}\)

\(x<{1\frac{1}{4}\;,\;x} > - \frac{1}{4}\)

x ning quyidagi tengsizlik bajariladigan barcha qiymatlarini toping: \(\left| {5x - 3} \right| < 7\)

-1; 0; 1; 2

0; 1; 2

0; 1

-1; 0; 1

Tenglama ildizlari ko‘paytmasini toping: \({\left| {x - 2} \right|^2} - 6 = \left| {x - 2} \right|\)

-32

-5

5

32

Tengsizlikni qanoatlantiruvchi butun sonlar nechta: \(\left| {2x - 5} \right| \le 1\)

1

4

3

2

Tengsizlikni butun yechimlar sonini aniqlang: \(\left| {x - 3} \right| \le 13\)

26 ta

28 ta

27 ta

25 ta

a ning qanday qiymatlarida \(\left| {a - 3} \right| = a - 3\) tenglik o‘rinli

\(a \ge 3\)

a>3

\(a \in \emptyset \)

a=3

Tenglamani yeching: \(\left| {x - a} \right| = \left| {x - 4} \right|\)

\(x = \frac{{a - 4}}{2}\)

\(x = \frac{{4 + a}}{2}\)

\(x = \frac{{4 - a}}{2}\)

\(x = \frac{{4 + a}}{4}\)

Tenglamani yeching: \(\left| {x - 1} \right| = \left| {x + 1} \right|\)

1

2

-1

0

Tenglamani yeching: \(\left| {x - 2} \right| = 2\)

\({x_1} = 0;\;{x_2} = 4\)

\({x_1} = 0;\;{x_2} = - 4\)

\({x_1} = 1;\;{x_2} = 4\)

\({x_1} = 0;\;{x_2} = 4\)

Tengsizlikni butun yechimlar yig‘indisini toping: \(\left| {3x - 7} \right| \le 7\)

10

8

\(11\frac{1}{3}\)

9

Teng yonli uchburchakning asosi 40 sm ga teng, perimetri 100 sm dan kichik. Shu uchburchak yon yomonini uzunligi qancha bo‘lishi mumkin?

\(a < 30\)

\(a < 35\)

\(a < 40\)

\(a < 34\)

Tengsizlikni yeching: \(\left| {1 - 2x} \right| \le 5\)

\( - 3 \le x \le 4\)

\( - 2 \le x \le 3\)

\( - 3 \le x \le 2\)

\( - 6 \le x \le 2\)

Tengsizlikni qanoatlantiruvchi butun sonlar ko‘paytmasini toping: \(\left| {7 - 4x} \right| \ge 9\)

0

\(\frac{{11}}{2}\)

\( - \frac{{11}}{4}\)

\( - 1\)

Tengsizlikni yeching: \(3 < \left| x \right| < 4\)

\(\left( { - 4;\; - 3} \right),\;\left( {3;4} \right)\)

\(\left[ { - 4;\; - 3} \right],\;\left[ {3;4} \right]\)

\(\left( { - 4;\; - 3} \right)\;,\;\left[ {3;4} \right]\)

\(\left[ { - 4;\; - 3} \right],\;\;\left( {3;4} \right)\)

a ning qanday qiymatlarida \(\left| x \right| \le a\) tengsizlik yechimlarga ega bo‘lmaydi?

istalgan qiymatida

\(a = 0\)

\(a < 0\)

\(a > 0\)

Tenglama ildizlari yig‘indisini toping: \({x^2} - 5\left| x \right| + 6 = 0\)

5

-5

10

0

\(a \le 0\;\)bo’lganda\(\;\left| x \right| \le a\) tengsizlikning yechimlarini toping.

\(x < 0\)

\(x > 0\)

\(x \le 0\)

istalgan son

Tenglamaning nechta ildizi bor: \(\left| x \right| = \left| {2x - 3} \right|\)?

3

1

2

cheksiz ko‘p

Tengsizlikni yeching: \(5 < \left| {x + 2} \right| < 9\)

\( - 7 < x < 7\)

\( - 7 < x < 3\) ;

\( - 11 < x < - 7;\;3 < x < 7\)

\( - 11 < x < 7\)

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