Report a question What's wrong with this question? You cannot submit an empty report. Please add some details. 123456789101112131415161718192021222324252627282930 matematika fanidan test savollari 5-variant Abiturentlar uchun matematika fanidan online test savollari. 5-variant Barcha ma'lumotlarni to'g'ri kiriting. \(f\left( x \right) = {\rm{lo}}{{\rm{g}}_2}\left( {x + \sqrt {1 + {x^2}} } \right)\) funksiya uchun quyidagilardan qaysi biri to‘g‘ri? Na Juft, Na Toq funksiya O’zgarmas funksiya Juft funksiya Toq funksiya Slindrning asosi tenglamasi \({x^2} + {\left( {y - 2} \right)^2} = 25\) bo‘lgan aylanadan iborat. Agar silindrning balandligi \(6\;{\rm{sm}}\) ga teng bo‘lsa, uning hajmi necha \(\pi \;{\rm{sm}}\) ga teng bo‘ladi? \(144\) \(100\) \(125\) \(150\) \({6^{46}}:23 = A\;\left( q \right)\) bo‘lsa, \(q\) ni toping. \(22\) \(12\) \(13\) \(21\) \(f\left( x \right) = {\left( {5{x^3} - 1} \right)^{2017}} \cdot {\left( {2016{x^7} + 1} \right)^5} + {x^{37}} + 14\) ko’phadning ozod hadini toping. \(13\) \(15\) \(12\) \(14\) \({2222^{5555}} + {5555^{2222}}\) sonini \(7\) ga bo‘lgandagi qoldiqni toping. \(0\) \(1\) \(5\) \(2\) \(\overline {ab} + \overline {bc} + \overline {ca} = \overline {abc} \) bo‘lsa, \(a \cdot b \cdot c\) ning qiymatini toping. \(90\) \(72\;\;\) \(60\) \(56\) \(x + \sqrt x = 3\) bo’lsa, \(\frac{{3 + x\sqrt x }}{{\sqrt x }}\) ning qiymatini toping. \(1\) \(4\) \(3\) \(2\) \(f\left( {{\rm{sin}}x} \right) + f\left( {{\rm{cos}}x} \right) = 3\) bo‘lsa, \(f\left( x \right)\) ni toping. \(3x\) \(3{x^2}\) \({\rm{\;}}{x^2}\) \(x\) \(\frac{1}{x} + \frac{1}{y} = \frac{3}{2}\) va \({2^x} = {3^y}\) bo‘lsa, \({8^x}\) ning qiymatini toping. \(36\) \(32\) \(34\) \(30\) \(\left( {\begin{array}{*{20}{c}}{EKUB\left( {x;y} \right) = 45}\\{\frac{x}{y} = \frac{{11}}{7}\;\;\;\;}\end{array}} \right.\) tenglamalar sistemasini yeching. \(\left( {220;\;175} \right)\) \(\left( {175;\;220} \right)\) \(\left( {315;\;495} \right)\) \(\left( {495;\;315} \right)\) \(\frac{1}{{x\left( {x + 1} \right)}} + \frac{1}{{\left( {x + 1} \right)\left( {x + 2} \right)}} + \frac{1}{{\left( {x + 2} \right)\left( {x + 3} \right)}} + \frac{1}{{\left( {x + 3} \right)\left( {x + 4} \right)}} + \frac{1}{{\left( {x + 4} \right)\left( {x + 5} \right)}}{\rm{\;}}\)ni soddalashtiring.\({\rm{\;}}\) \(\frac{5}{{x\left( {x + 5} \right)}}\) \(\frac{5}{{\left( {x + 4} \right)\left( {x + 5} \right)}}\) \(\frac{x}{{x + 5}}\) \(\frac{5}{{x + 5}}\) \(2x + 2y\) ko‘phadni ko‘paytuvchilarga ajrating. \(2 \cdot \left( {x + y} \right)\) \(2 \cdot \left( {x + 2y} \right)\) \(2 \cdot \left( {2x + 2y} \right)\) \(\;2 \cdot \left( {2x + y} \right)\) Quyidagi rasmda ko‘rsatilgan ma’lumotlardan foydalanib, \(x\) ning qiymatini toping. \(\sqrt {21} \) \(5\) \(6\) \(\sqrt {23} \) \(ABCD\) parallelogrammning tomonlari \(AB = 25\;{\rm{sm}}\) va \(BC = 34\;{\rm{sm}}\) ga teng. \(DC\) tomonga \(BH\) balandlik tushirilgan hamda \(BC\) tomondan \(M\) va \(AD\) tomondan \(N\) nuqta olingan. \(MN\) kesma \(AD\) tomonga perpendikulyar va \(BH\) ni \(K\) nuqtada kesib o‘tadi. Agar \(MN = \frac{{375}}{{11}}\;{\rm{sm}}\) va \(BK = KH\) bo‘lsa, \(AK\) kesma uzunligini \(\left( {{\rm{sm}}} \right)\) toping. \(5\sqrt {34} \) \(10\sqrt {31} \) \(20\) \(28\) \(\frac{{{7^x} + 7}}{{{7^x} - 7}} + \frac{{{7^x} - 7}}{{{7^x} + 7}} \ge \frac{{4 \cdot {7^x} + 96}}{{{{49}^x} - 49}}\) tengsizlikni yeching. \(x \in \left\{ { - 1} \right\} \cup \left( {7;\;\infty } \right)\) \(x \in \left\{ { - 1} \right\} \cup \left( {7;\;\infty } \right)\) \(x \in \left( { - \infty ;\; - 7} \right) \cup \left\{ { - 1} \right\} \cup \left( {7;\;\infty } \right)\) \(x \in \left( { - \infty ;\; - 7} \right) \cup \left\{ 1 \right\} \cup \left( {7;\;\infty } \right)\) \(5\sqrt 2 \sin \frac{{3\pi }}{8}\cos \frac{{3\pi }}{8}\) ning qiymatini toping. \(5\) \(5\sqrt 2 \) \(2,5\sqrt 2 \) \(2,5\) \(3{a^2} - 4ab + {b^2} = 0\) bo‘lsa, \(a\) ni \(b\) orqali ifodalang. \(a = \frac{b}{3}\) va \(a = b\) \(a = \frac{{2b}}{3}\) va\(\;a = 2b\) \(a = 0,5b\) va \(a = 3b\) \(a = 3b\) va \(a = 2b\) \(\vec a\left( {3;\;7} \right)\) va \(\vec b\left( {8;9} \right)\) bo‘lsa, \(1,2\vec a - 0,7\vec b\) vektorning uzunligini toping. \(29\) \(2,9\) \(27\) \(2,7\) Quyidagi rasmda \(y = f\left( x \right)\) funksiya grafigi tasvirlangan: \(\mathop \smallint \nolimits_{ - 4}^{ - 3} f\left( x \right)dx = 2\;\)va\(\;{S_3} - {S_2} = 2\) bo‘lsa, \(\mathop \smallint \nolimits_{ - 2}^{ - 4} f\left( x \right)dx\)ning qiymatini toping. \( - 2\) \(2\) \( - 4\) \(4\) \(64 \cdot {9^x} - 84 \cdot {12^x} + 27 \cdot {16^x} = 0\) tenglamaning haqiqiy ildizlari ko‘paytmasini toping. \(2\) \(12\) \(1\) \(4\) Formula \(3\) ta kitob ichidan qidirilyapti. Formulaning birinchi kitobdan topilish ehtimoli \(0,6\) ga, ikkichi kitobdan topilish ehtimoli \(0,7\) ga, uchinchi kitobdan topilish ehtimoli \(0,8\) ga teng bo‘lsa, formulaning faqat \(2\) ta kitobdan topilish ehtimolini toping. \(0,224\) \(0,084\) \(0,144\) \(0,452\) \(x \ne 10\) va \(f\left( x \right) = \sqrt[3]{{x\left( {20 - x} \right)}}\) bo‘lsa, \(\frac{{f\left( {10 - x} \right)}}{{f\left( {10 + x} \right)}}\) ning qiymatini toping. \( - 1\) \(1\) \(\sqrt[3]{{\frac{{10 - x}}{{10 + x}}}}\) \(\sqrt[3]{{\frac{{10 + x}}{{10 - x}}}}\) Quyidagi chizmada olcha daraxtining shoxlari ko‘rsatilgan: Agar \(AB//ED\) bo‘lsa, \(\angle BCD\) ni toping. \(80^\circ \) \(60^\circ \) \(90^\circ \) \(70^\circ \) \(y = 8x + 19\) funksiyani \(\vec m\left( {6;3} \right)\) vektor bo‘yicha parallel ko‘chirsak, qanday funksiya hosil bo‘ladi? \(y = 8x - 29\) \(y = 8x + 23\) \(y = 8x - 23\) \(y = 8x - 26\) Quyidagi rasmda markazi koordinatalar boshida bo‘lgan aylana tasvirlangan:\(K\) va \(L\) nuqtalarning absissalari mos ravishda \(\frac{1}{{\sqrt 5 }}\) va \(\frac{3}{{\sqrt {10} }}\) ga teng bo‘lsa, \(\alpha \) ni toping. \(22,5^\circ \) \(45^\circ \) \(30^\circ \) \(60^\circ \) Quyidagi rasmda tasvirlangan doiralardan eng kattasining radiusi \(4\;{\rm{sm}}\) ga teng.Qolgan har bir doiraning radiusi o‘zidan oldingi doira radiusining \(\frac{3}{4}\) qismini tashkil qiladi. Bunga ko‘ra barcha doiralarning yuzlari yig‘indisini \(\left( {{\rm{s}}{{\rm{m}}^2}} \right)\) toping. \(\frac{{256}}{7} \cdot \pi \) \(8 \cdot \pi \) \(\frac{{128}}{7} \cdot \pi \) \(16 \cdot \pi \) Quyidagi rasmda \(f\left( x \right) = {a^x}\) funksiya grafigi tasvirlangan:Rasmda berilgan ma’lumotlardan foydalanib, \(f\left( 4 \right)\) ning qiymatini toping. \(\frac{1}{{81}}\) \(9\) \(3\) \(81\) \(1 \cdot 2 \cdot 3 \cdot \ldots \cdot 54 \cdot 55\) ko‘paytma nechta nol bilan tugaydi? \(22\) \(20\) \(13\) \(11\) \(f\left( x \right) = {3^x} \cdot {\rm{tg}}x\) bo’lsa, \(f'\left( 0 \right)\) ning qiymatini toping. \(3\ln 3\) \(\ln 3\) \(1\) \(3\) \(\sqrt {6x - 57} = 9\) tenglama nechta haqiqiy ildizga ega? \(3\) \(0\) \(1\) \(2\) Facebook Twitter VKontakte 0% Перезапустить тест